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(A) Given the quadratic equation: $x^{2} - 7 = 0$. We can rewrite this as: $x^{2} - (\sqrt{7})^{2} = 0$. Using the algebraic identity $a^{2} - b^{2} =

Vedclass · Accepted Answer

$-\sqrt{7}, \sqrt{7}$

Vedclass · Answer

(A) Given the quadratic equation: $x^{2} - 7 = 0$. We can rewrite this as: $x^{2} - (\sqrt{7})^{2} = 0$. Using the algebraic identity $a^{2} - b^{2} = (a - b)(a + b)$,we get: $(x - \sqrt{7})(x + \sqrt{7}) = 0$. Setting each factor to zero: $x - \sqrt{7} = 0 \implies x = \sqrt{7}$. $x + \sqrt{7} = 0 \implies x = -\sqrt{7}$. Thus,the solutions are $x = \sqrt{7}$ and $x = -\sqrt{7}$.

Solve the following equation using the method of factorization: $x^{2} - 7 = 0$.

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